$C O_{2}$ is released when $N a_{2} C O_{3}$ reacts with :

concentrated

H_{2} S O_{4}

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dilute HCl

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H_{2} O

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dilute

H_{2} S O_{4}

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Solution

The correct option is D dilute $H_{2} S O_{4}$
When sodium carbonate is treated with dilute $H_{2} S O_{4}, C O_{2}$ is released which gives brisk effervescence. The gas evolved turns lime water milky.
$N a_{2} C O_{3} + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O + C O_{2}$

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