CO2(O−C−O)is a triatomic gas. Mean kinetic energy of one-gram gas will be
(If N, Avogadro number; k, Boltzmann constant and molecular weight of CO2=44)
A
3/88NkT
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B
6/88NkT
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C
5/88NkT
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D
7/88NkT
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Solution
The correct option is D7/88NkT We know that: E=f2μRTalsoR=NK E=f2μNKT CO2f=7.μ=144 E=72×144NKT E=788NKT