Co60 emerging from a source at a speed (v) has a de Broglie wavelength of 11.0 ∘A. The value of v (inms–1) is closest to [Planck’s constant h = 6.626×10–34Js]
A
0.5
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B
2.5
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C
5
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D
30
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Solution
The correct option is A 0.5 λ=hmv⇒v=hmλMassofCo60is=720.66g/molSo,for1atomm=720×10−36.022×1023=6.62×10−34×6.022×1023720×10−3×11×10−10=0.5m/s