$[C o (e n)_{2} (N H_{3}) C l]^{2 +}$ is known to be a diamagnetic complex. What is the type of hybridisation it shows ?

d s p^{2}

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s p^{3}

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d^{2} s p^{3}

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s p^{3} d^{2}

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Solution

The correct option is C $d^{2} s p^{3}$
$C o^{3 +} has 3 d^{6}$ configuration.
For a complex to be diamagnetic, it should have no unpaired electrons. So, in the cobalt complex given all the six electrons pair up in 3 d-orbitals leaving two empty d-orbitals for hybridization with s and p orbitals to give $d^{2} s p^{3}$ hybridisation. Thus option (c) is the correct answer

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[Co(en)2(NH3)Cl]2+ is known to be a diamagnetic complex. What is the type of hybridisation it shows ?

$[C o (e n)_{2} (N H_{3}) C l]^{2 +}$ is known to be a diamagnetic complex. What is the type of hybridisation it shows ?