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Question

CO(g)+12O2(g)CO2(g)
The value of standard change in enthalpy for the above reaction on the basis of the following data is:
T=300 K, ΔSo=0.094 kJmol1K1,ΔGof(CO2)=394.4 kJmol1 and ΔG0f(CO)=137 kJmol1

A
285.4 kJ/mol
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B
28.54 kJ/mol
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C
285.4 kJ/mol
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D
none of these
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Solution

The correct option is A 285.4 kJ/mol
CO+12O2CO2
ΔGorK=ΔGof(CO2)ΔfGo(CO)
=394.4+137
=257.4kJ/mol
ΔHrknTΔS=257.4
ΔH=257.4+300×(0.094)
=257.4+(28.2)
=285.6kJ/mol.

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