Question 25

CO is isoelectronic with

(a) $N O^{+}$

(b) $N_{2}$

(c) $S n C l_{2}$

(d) $N O_{2}^{-}$

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Solution

Answers:

(a) $N O^{+}$

(b) $N_{2}$

Electrons present in CO = 6 + 8 =14

Then, In $N O^{+}$ = 7 + 8 - 1 =14

In $N_{2}$ = 7 + 7 = 14

In $S n C l_{2}$ = (very high) 50 + 17 $\times$ 2 = 50 + 34 = 84

In $N O_{2}^{-}$ = 7 +16 + 1 = 24

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