The correct option is D Ionisation isomerism
[Co(NH3)5Br]SO4 and [Co(NH3)5SO4]Br are ionisation isomers. This form of isomerism arises when the counter ion in a complex salt is itself a potential ligand and can displace a ligand which can then become the counter ion.
Above two complex can be distinguished by test.
Aqueous solution of [Co(NH3)5Br]SO4 will give a white ppt in BaCl2 solution. The ppt is insoluble in conc. HNO3 confirming presence of free SO−24 ion. Aqueous solution of [Co(NH3)5SO4]Br will not give the test.
⇒[Co(NH3)5Br]SO4⇋[Co(NH3)5Br]2++SO−24
BaCl2+SO−24→BaSO4↓+2Cl−
White ppt
⇒[Co(NH3)5SO4]Br⇋[Co(NH3)5SO4]++Br−
BaCl2+Br−→No ppt.