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Nomenclature of Coordination Compounds

[CoNH35SO4]Cl...

Question

$[C o (N H_{3})_{5} S O_{4}] C l$ is an octahedral coordination compound.
Write the formula of the ionisation isomer of the compound.

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Solution

Formula of the ionisation isomer of the given compound is $[C o {(N H_{3})}_{5} C l] S O_{4}$ .

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[C o (N H_{3})_{5} S O_{4}] C l

is an octahedral coordination compound. Write the IUPAC name of the above coordination compound.

[C o (N H_{3})_{5} S O_{4}] C l

is an octahedral coordination compound.

Draw the diagram which indicate the splitting of 'd' orbitals in tetrahedral field.

Q. Write the formula of ionisation isomer of

[C r (H_{2} O)_{4} B r_{2}] C l

Q. The octahedral complex

C o S O_{4} C l .5 N H_{3}

exists in two isomeric forms X and Y. Isomer X reacts with

A g N O_{3}

to give a white precipitate, but does not react with

B a C l_{2}

. Isomer Y gives white precipitate with

B a C l_{2}

but does not react with

A g N O_{3}

. Isomer X and Y are

Q. The ionisation isomer of

[C r {(H_{2} O)}_{4} C l (N O_{2})] C l

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