Coagulation value of the electrolytes $A l C l_{3}$ and $N a C l$ for $A s_{2} S_{3}$ sol are $0.093$ and $52$ repectively. How many times $A l C l_{3}$ has greater coagulating power than $N a C l$ ?

930

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520

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560

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None of these

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Solution

The correct option is C $560$
$\frac{Coagulation power of A l C l_{3}}{Coagulation power of N a C l} = \frac{Coagulation power of N a C l}{Coagulation power of A l C l_{3}} = \frac{52}{0.093} \approx 560$

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Coagulation values of the electrolytes $A l C l_{3}$ and $N a C l$ for $A s_{2} S_{3}$ solution are $0.093$ and $52$ respectively. How many times $A l C l_{3}$ has a greater coagulating power than $N a C l$ ?

Q. The coagulation values in millimoles per litre of the electrolytes used for the coagulation of

A s_{2} S_{3}

are given below:

I . (N a C l) = 52, I I . (B a C l_{2}) = 0.69, I I I . (M g S O_{4}) = 0.22

The correct order of their coagulating power is

Q. The coagulation values in millimoles per litre of the electrolytes used for the coagulation of

A s_{2} S_{3}

are given below :
(I) for

N a C l, i t i s 52,

(II) for

B a C l_{2}, i t i s 0.69,

(III) for

M g S O_{4}, i t i s 0.22

The correct order of their coagulating power is

Q. The coagulation values in millimoles per litre of the electrolytes used for the coagulation of

A s_{2} S_{3}

are given below:

I . (N a C l) = 52, I I . (B a C l_{2}) = 0.69, I I I . (M g S O_{4}) = 0.22

The correct order of their coagulating power is

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Coagulation value of the electrolytes AlCl3 and NaCl for As2S3 sol are 0.093 and 52 repectively. How many times AlCl3 has greater coagulating power than NaCl?

The correct option is C 560Coagulation power ofAlCl3Coagulation power ofNaCl=Coagulation power ofNaClCoagulation power ofAlCl3=520.093≈560

Coagulation value of the electrolytes $A l C l_{3}$ and $N a C l$ for $A s_{2} S_{3}$ sol are $0.093$ and $52$ repectively. How many times $A l C l_{3}$ has greater coagulating power than $N a C l$ ?

The correct option is C $560$
$\frac{Coagulation power of A l C l_{3}}{Coagulation power of N a C l} = \frac{Coagulation power of N a C l}{Coagulation power of A l C l_{3}} = \frac{52}{0.093} \approx 560$