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Werner's Coordination Theory

Cobalt III ch...

Question

Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at $25^{\circ} C$ ?

A

CoCl₃.6NH₃

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B

CoCl₃.3NH₃

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C

CoCl₃.4NH₃

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D

CoCl₃.5NH₃

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Solution

The correct option is B
CoCl₃.3NH₃

$C o C l_{3} .3 N H_{3}$ doesn‘t ionize so doesn‘t give test for chloride ions.

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Similar questions

Q. Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at

25^{\circ} C

Q. When 0.01 mole of a cobalt complex is treated with excess silver nitrate solution, 4.305 g silver chloride is precipitated. The formula of the complex is:

Q. Only two-third of the chlorine contained in the solution of the complex salt

C o C l_{3} \cdot 5 N H_{3}

were precipitated from it by silver nitrate. No cobalt or free ammonia were detected in the solution of the salt.

The electrical conductivity of the solution shows that the salt dissociates into three ions. What is the coordination structure of the complex salt?

Q. 2.66 g chloride of a metal when treated with silver nitrate solution give 2.87 g of silver chloride. 3.37 g of another chloride of the same metal give 5.74 g of silver chloride when treated with silver nitrate solution. Show that the results are in agreement with a law of chemical combination.

Q. The number of chloride ions which would be precipitated, when

C r C l_{3} .4 N H_{3}

is treated with silver nitrate solution:

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