CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at 25oC?

A
CoCl35NH3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
CoCl36NH3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
CoCl33NH3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
CoCl34NH3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D CoCl33NH3
CoCl33NH3 will not give test for chloride ions with silver nitrate at 25oC.
The coordination number of Co is six. 3 ammonia ligands are present in the coordination sphere. Hence, 3 chloride ligands must be present in the coordination sphere.
CoCl33NH3 can also be written as [CoCl3(NH3)3].
Since, all the chloride ions are present in the coordination sphere, they are firmly attached to metal and do not ionize in solution.
Hence, they cannot form precipitate of AgCl with AgNO3 solution.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Imperfections in Solids
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon