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Question

[CoCl2(NH3)4]++Cl[CoCl3(NH3)3]+NH3. If in this reaction two isomers of the product are obtained, which is true for the inital (reactant) complex :

A
compound is in cis-form
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B
compound is in trans-form
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C
compound is in both (cis and trans) form
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D
can't be predicted
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Solution

The correct option is D compound is in cis-form
When the reactant [CoCl2(NH3)4]+ is in cis form, the product [CoCl3(NH3)3] will have have cis (or fac or facial) isomer and trans (or mer or meridional ) isomer.
When the reactant [CoCl2(NH3)4]+ is in trans form, the product [CoCl3(NH3)3] will have have only trans (or mer or meridional ) isomer.
Since two isomers of the product are obtained, the reactant is in cis form.

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