The correct option is D compound is in cis-form
When the reactant [CoCl2(NH3)4]+ is in cis form, the product [CoCl3(NH3)3] will have have cis (or fac or facial) isomer and trans (or mer or meridional ) isomer.
When the reactant [CoCl2(NH3)4]+ is in trans form, the product [CoCl3(NH3)3] will have have only trans (or mer or meridional ) isomer.
Since two isomers of the product are obtained, the reactant is in cis form.