[CoCl4]2− (blue) and [Co(H2O)6]2+ (pink) have different colours because of Δtet<Δoct. If true enter 1, else enter 0.
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Solution
The correct answer is 1.
[CoCl4]2− (blue) and [Co(H2O)6]2+ (pink) have different colours because of Δtet<Δoct. The [Co(H2O)6]2+ complex is pink due to d−d transition, Δoct absorbs blue colour and the complimentary color red/pink is seen( weak absorbance).
The [CoCl4]2− complex is a deeper blue as d−d transition requires smaller energy. Δtet absorbs red (more strongly) and it appears blue.