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Question

Coefficient of a32 in the expansion of(a4−1a3)15 is

A
15C4
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B
15C4
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C
0
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D
15C3
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Solution

The correct option is B 15C4
Tr+1=nCranrbr
Applying to the above question we get
Tr+1=(1)r15Cra604ra3r
=(1)r15Cra607r ...(i)
For the coefficient of a32
607r=32
28=7r
r=4
Substituting in (i) we get
T5=15C4a32
Thus the required coefficient is 15C4

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