Coefficient of volume expansion of mercury is 0-18 - 10 - 3 - 0 C - If the density of mercury at 0 - C is 13-6 g-cc- then its density at 200 - C is

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Standard XII

Physics

Area and Volume Expansion

Coefficient o...

Question

Coefficient of volume expansion of mercury is $0.18 \times 10^{- 3 / 0} C .$ If the density of mercury at $0^{\circ} C$ is $13.6 g / c c,$ then its density at $200^{\circ} C$ is

13.11 g / c c

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52.11 g / c c

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16.11 g / c c

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26.11 g / c c

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Solution

The correct option is A $13.11 g / c c$
Coefficient of volume expansion $0.18 \times 10^{- 3} %$
$\begin{matrix} ρ = \frac{ρ_{0}}{(1 + r_{0} r)} = \frac{13.6}{1 + (0.18 \times 10^{- 3}) (200^{\circ} C)} = \frac{13.6}{1 + 0.036} = 13.11 g / c c \end{matrix}$
Option A.

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Coefficient of volume expansion of mercury is 0.18×10−3/0C. If the density of mercury at 0∘C is 13.6g/cc, then its density at 200∘C is

The correct option is A 13.11g/ccCoefficient of volume expansion 0.18×10−3%ρ=ρ0(1+r0r)=13.61+(0.18×10−3)(200∘C)=13.61+0.036=13.11g/ccOption A.

Coefficient of volume expansion of mercury is $0.18 \times 10^{- 3 / 0} C .$ If the density of mercury at $0^{\circ} C$ is $13.6 g / c c,$ then its density at $200^{\circ} C$ is

The correct option is A $13.11 g / c c$
Coefficient of volume expansion $0.18 \times 10^{- 3} %$
$\begin{matrix} ρ = \frac{ρ_{0}}{(1 + r_{0} r)} = \frac{13.6}{1 + (0.18 \times 10^{- 3}) (200^{\circ} C)} = \frac{13.6}{1 + 0.036} = 13.11 g / c c \end{matrix}$
Option A.