Coefficient of volume expansion of mercury is 0-18- 10 -3 -C- If the density of mercury at 0 -C is 13-6 g-cc- then its density at 200 -C is

The correct option is A 13.11 g/cc ρ = ρ_0/1+r_0t #160; #160;= 13.6/1+0.18×(200^∘C) #160; #160;= 13.6/1.036 = 13.11 ...

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Standard XII

Physics

Bulk Modulus

Coefficient o...

Question

Coefficient of volume expansion of mercury is $0.18 \times 10^{- 3} /^{\circ} C$ . If the density of mercury at $0^{\circ} C$ is 13.6 g/cc, then its density at $200^{\circ} C$ is

13.11 g/cc

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Solution

The correct option is A 13.11 g/cc
$ρ = \frac{ρ_{0}}{1 + r_{0} t}$

= $\frac{13.6}{1 + 0.18 \times (200^{\circ} C)}$

= $\frac{13.6}{1.036}$ = 13.11

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Coefficient of volume expansion of mercury is 0.18×10−3/∘C. If the density of mercury at 0∘C is 13.6 g/cc, then its density at 200∘C is

The correct option is A 13.11 g/ccρ=ρ01+r0t =13.61+0.18×(200∘C) = 13.61.036 = 13.11

Coefficient of volume expansion of mercury is $0.18 \times 10^{- 3} /^{\circ} C$ . If the density of mercury at $0^{\circ} C$ is 13.6 g/cc, then its density at $200^{\circ} C$ is

The correct option is A 13.11 g/cc
$ρ = \frac{ρ_{0}}{1 + r_{0} t}$

= $\frac{13.6}{1 + 0.18 \times (200^{\circ} C)}$

= $\frac{13.6}{1.036}$ = 13.11