The correct option is C 1113
Coeff. of x11 in exp. of (1+x2)4(1+x3)7(1+x4)12(Coeff.of xa)×(Coeff.of xb)×(Coeff.of xc)Such that a+b+c=11Here a=2m,b=3n,c=4p∴2m+3n+4p=11Case I :m=0,n=1,p=2Case II :m=1,n=3,p=0Case III :m=2,n=1,p=1Case IV :m=4,n=1,P=0∴Required coeff. =4C0×7C1×12C2+4C1×7C3×12C0+4C2×7C1×12C1+4C4×7C1×12C0=462+140+504+7=1113