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Question

Coefficient of x11in the expansion of (1+x2)4(1+x3)7(1+x4)12 is

A
1051
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B
1106
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C
1113
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D
1120
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Solution

The correct option is C 1113
Coeff. of x11 in exp. of (1+x2)4(1+x3)7(1+x4)12(Coeff.of xa)×(Coeff.of xb)×(Coeff.of xc)Such that a+b+c=11Here a=2m,b=3n,c=4p2m+3n+4p=11Case I :m=0,n=1,p=2Case II :m=1,n=3,p=0Case III :m=2,n=1,p=1Case IV :m=4,n=1,P=0Required coeff. =4C0×7C1×12C2+4C1×7C3×12C0+4C2×7C1×12C1+4C4×7C1×12C0=462+140+504+7=1113

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