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Question

Coefficient of x7 in the expansion of (1−2x+x3)6 is

A
280
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B
360
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C
450
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D
280
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Solution

The correct option is B 360
x7 implies (x3)2(2x)1(1)3
The coefficient being =6!.(2)2!3!1!
And (x3)(2x)4(1)1
The coefficient being =6!.(2)41!4!1!
Hence the coefficient of x7 in the above expansion is
6!.(2)2!3!1!+6!.(2)41!4!1!
=120+480
=360

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