CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Coefficients of friction between the flat bed of the truck and crate are μs=0.8 and μk=0.7. The coefficient of kinetic friction between the truck tires and the road surface is 0.9. If the truck stop from an initial speed 15m/s with maximum braking (wheels skidding). Determine where on the bed the crate finally comes to rest. (Take g=10m/s2)

239108_eca456eb78dd498da4aad0224cfb1614.png

A
2.77m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2.37m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.77m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2.77m
let the mass of the truck be M then friction force on it is
F=μMg=Ma
a=μg=0.9g

time for truck to come at rest
Vf=Vi+at
0=150.9gt
t=53s

friction between crate and truck surface is
F=mμkg
a=0.7g=7m/s2

so relative acceleration is 97=2m/s2
the distance the crate will travel is
S=ut+12at2
S=0+12×2×(53)2
S=2.77m


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon