Question

Cold, dilute nitric acid react with copper to form………..

Answer 1

1. Cold, dilute nitric acid $\mathbf{\left(}{\mathbf{HNO}}_{\mathbf{3}}\mathbf{\right)}$reacts with copper $\mathbf{\left(}\mathbf{Cu}\mathbf{\right)}$ to form copper nitrate $\mathbf{\left(}\mathbf{Cu}{\mathbf{\left(}{\mathbf{NO}}_{\mathbf{3}}\mathbf{\right)}}_{\mathbf{2}}\mathbf{\right)}$, water$\mathbf{\left(}{\mathbf{H}}_{\mathbf{2}}\mathbf{O}\mathbf{\right)}$ and nitric oxide $\mathbf{\left(}\mathbf{NO}\mathbf{\right)}$ as a product.
2. The chemical equation can be represented as:

$\underset{\left(\mathrm{Copper}\right)}{\underbrace{3\mathrm{Cu}\left(\mathrm{s}\right)}}+\underset{(\mathrm{Nitric}\mathrm{acid})}{\underbrace{8{\mathrm{HNO}}_3\left(\mathrm{aq}\right)}}\to \underset{(\mathrm{Copper}\mathrm{nitrate})}{\underbrace{3\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{aq}\right)}}+\underset{\left(\mathrm{Water}\right)}{\underbrace{4{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}}+\underset{(\mathrm{Nitric}\mathrm{oxide})}{\underbrace{2\mathrm{NO}\left(\mathrm{g}\right)}}$

So, cold, dilute nitric acid reacts with copper to form copper nitrate, water and nitric oxide.