Question

Cold ferrous sulphate solution on absorption of $NO$ develops brown colour due to the formation of:

• A. paramagnetic $\left[Fe\right(H_{2}O{)}_5\left(NO\right)]S{O}_4$
• B. diamagnetic $\left[Fe\right(H_{2}O{)}_5\left(N_3\right)]S{O}_4$
• C. paramagnetic $\left[Fe\right(H_{2}O{)}_5\left(N{O}_3\right)\left]\right(S{O}_4{)}_2$
• D. diamagnetic $\left[Fe\right(H_{2}O{)}_4\left(S{O}_4\right)]N{O}_3$

Answer 1

Answer: (A)

paramagnetic $\left[Fe\right(H_{2}O{)}_5\left(NO\right)]S{O}_4$

Cold ferrous sulphate solution on absorption of $NO$ develops brown colour due to the formation of paramagnetic $\left[Fe\right(H_{2}O{)}_5\left(NO\right)]S{O}_4$.

$\underset{cold}{FeS{O}_4}+5H_{2}O+NO\to \left[Fe\right(H_{2}O{)}_5\left(NO\right)]S{O}_4$