Colourless salt $(A) + d i l . H_{2} {S O}_{4} + K I ⟶$ blue colour with solution. $A$ can be :

K_{2} {C r}_{2} O_{7}

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{M n O}_{2}

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{N H}_{4} {N O}_{2}

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{N H}_{4} C l

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Solution

The correct option is C ${N H}_{4} {N O}_{2}$
The colourless salt (A) can be ammonium nitrite $({N H}_{4} {N O}_{2})$ .
It reacts with dil sulphuric acid to form nitrous acid which converts $K I$ to iodine which is violet in colour.
${N H}_{4} {N O}_{2} + H_{2} S O_{4} \to N H_{4} S O_{4} + 2 H N O_{2}$
$3 H N O_{2} \to H N O_{3} + 2 N O + H_{2} O$
$2 N O + O_{2} \to 2 N O_{2}$
$2 K I + 2 N O_{2} \to K N O_{2} + I_{2}$

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Similar questions

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

[X] + H_{2} {S O}_{4} ⟶ [Y]

[Y] + K_{2} {C r}_{2} O_{7} + H_{2} {S O}_{4} ⟶

K_{2} {C r}_{2} O_{7} + c o n c . H_{2} {S O}_{4} + H_{2} O_{2} + e t h e r ⟶

({N a}_{2} {S O}_{3} + K_{2} {C r}_{2} O_{7})

d i l . H_{2} {S O}_{4}

K_{2} {C r}_{2} O_{7} + {a H}_{2} {S O}_{4} + {b S O}_{2} \to K_{2} {S O}_{4} + {C r}_{2} {(S O}_{4})_{3} + {c H}_{2} O

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