Column 1- 2 and 3 contains starting material- formula of the product and structure of the product respectively- beginarray - - hline - -Column 1 - -Column 2 - -Column 311 hlineII-White P4-alkali rightarrow -ii-N2O-Q-Tetrahedralwith one - OH WhlineIV-P2O3-H2O sightarrow -iv-N2O2-S-Linearillhline lendarray The correct set in which phosphorous atom is in -3 state-A- IV - i -QB- II - i - QC- II - i - RD- IV - i - R

The correct option is D (IV) . (i) . (R)P_2O_3+H_2O→ 2H_3PO_3 ...

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Byju's Answer

Standard XII

Chemistry

Hydrate Isomerism

Column 1, 2 a...

Question

Column 1, 2 and 3 contains starting material, formula of the product and structure of the product respectively.
$\begin{matrix} C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (I) & N H_{4} N O_{3} Δ - \to & (i) & H_{3} P O_{3} & (P) & A n g u l a r (I I) & W h i t e P_{4} + a l k a l i \to & (i i) & N_{2} O & (Q) & T e t r a h e d r a l (w i t h o n e - O H) (I I I) & P b (N O_{3})_{2} 673 K - -- \to & (i i i) & H_{3} P O_{2} & (R) & T e t r a h e d r a l (w i t h t w o - O H) (I V) & P_{2} O_{3} + H_{2} O \to & (i v) & N_{2} O_{2} & (S) & L i n e a r \end{matrix}$
The correct set in which phosphorous atom is in +3 state?

(II) . (i) . (Q)

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(IV) . (i) . (Q)

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(II) . (i) . (R)

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(IV) . (i) . (R)

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Solution

The correct option is D (IV) . (i) . (R)
$P_{2} O_{3} + H_{2} O \to 2 H_{3} P O_{3}$

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Similar questions

Q. Column 1, 2 and 3 contains starting material, formula of the product and structure of the product respectively.

\begin{matrix} C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (I) & N H_{4} N O_{3} Δ - \to & (i) & H_{3} P O_{3} & (P) & A n g u l a r (I I) & W h i t e P_{4} + a l k a l i \to & (i i) & N_{2} O & (Q) & T e t r a h e d r a l (w i t h o n e - O H) (I I I) & P b (N O_{3})_{2} 673 K - -- \to & (i i i) & H_{3} P O_{2} & (R) & T e t r a h e d r a l (w i t h t w o - O H) (I V) & P_{2} O_{3} + H_{2} O \to & (i v) & N_{2} O_{2} & (S) & L i n e a r \end{matrix}

The correct set which is representing the colourless gas neutral in nature?

Q. Column 1, 2 and 3 contains starting material, formula of the product and structure of the product respectively.

\begin{matrix} C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (I) & N H_{4} N O_{3} Δ - \to & (i) & H_{3} P O_{3} & (P) & A n g u l a r (I I) & W h i t e P_{4} + a l k a l i \to & (i i) & N_{2} O & (Q) & T e t r a h e d r a l (w i t h o n e - O H) (I I I) & P b (N O_{3})_{2} 673 K - -- \to & (i i i) & H_{3} P O_{2} & (R) & T e t r a h e d r a l (w i t h t w o - O H) (I V) & P_{2} O_{3} + H_{2} O \to & (i v) & N_{2} O_{2} & (S) & L i n e a r \end{matrix}

The correct set in which highly unstable brown colored gas, which can be dimerised also is formed:

A diatomic ideal gas undergoes expansion through different processes shown in the column-I. Answer the following questions based on these columns.
$\begin{matrix} C o l u m n I & C o l u m n 2 & C o l u m n 3 (I) & P^{2} \propto \frac{1}{V^{3}} & (i) & Δ T > 0 & (P) & Δ Q > 0 (I I) & T^{5} \propto \frac{1}{V} & (i i) & Δ T < 0 & (Q) & Δ Q = 0 (I I I) & P^{5} \propto \frac{1}{V^{7}} & (i i i) & Δ T = 0 & (R) & Δ Q < 0 (I V) & P^{5} \propto \frac{1}{V^{4}} & (i v) & C a n^{'} t s a y & (S) & C a n^{'} t s a y \end{matrix}$
Choose the correct combination for adiabatic process?

Column 1: Compound Column

Column 2: Oxidation state Column

Column 3: Type of linkage

$\begin{matrix} Column 1 & Column 2 & Column 3 (I) & N a_{2} S_{2} O_{3} & (i) & + 5 & (P) & S - O - S (I I) & N a_{2} S_{4} O_{6} & (i i) & - 2 & (Q) & - S - S - (I I I) & H_{2} S_{2} O_{7} & (i i i) & + 6 & (R) & - O - O - (I V) & H_{2} S_{2} O_{8} & (i v) & + 4 & (S) & S = S \end{matrix}$

The only correct combination in which the oxidation state of one of the S is zero:

Q. Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively:

\begin{matrix} Column 1 & Column 2 & Column 3 (I) Toluene & (i) N a O H / B r_{2} & (P) Condensation (II) Acetophenone & (i i) B r_{2} / h v & (Q) Carboxylation (III) Benzaldehyde & (i i i) (C H_{3} C O)_{2} O / C H_{3} C O O K & (R) Substitution (IV) Phenol & (i v) N a O H / C O_{2} & (S) Haloform \end{matrix}

The only CORRECT combination that gives two different carboxylic acids is:

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The correct option is D (IV) . (i) . (R)P2O3+H2O→2H3PO3

The correct option is D (IV) . (i) . (R)
$P_{2} O_{3} + H_{2} O \to 2 H_{3} P O_{3}$