Question

Column 1 Column II

A) Dilute solution of $HCl$ (P) $O_2$ evolved at anode

B) Dilute solution of $KCl$ (Q) $H_2$ evolved at Cathode

C) Concentrate solution of $NaCl$ (R) $C{l}_2$ evolved at anode

D) Fairly concentrate solution of $AgN{O}_3$ (S) Ag deposition at cathode

• A. A-R; B-Q; C-R, S ; D-P,Q
• B. A-P, R; B-P, Q; C-S; D-P,S
• C. A-P, Q; B-P, Q; C-Q, R; D-P, S
• D. A-S; B-Q, R; C-P; D-Q

Answer 1

The correct option is C A-P, Q; B-P, Q; C-Q, R; D-P, S

During electrolysis of dilute $HCl$ (or dilute $KCl$) solution, the water dissociates to form hydrogen and oxygen. Hydrogen is evolved at cathode and oxygen is evolved at the anode.

During electrolysis of concentrated $NaCl$ solution, at cathode hydrogen is obtained from water and at the anode, chlorine is obtained from $NaCl$.

During electrolysis of fairly concentrated silver nitrate, at the anode, oxygen is evolved from water and at the cathode, silver is deposited.