Question

Column 1 Column II

A) $\wedge {{}^0}_m\left(NaN{O}_3\right)$ (P) Can be obtained by

Kohlraush law

B) $\wedge {{}^0}_m$ (Q) Can be obtained by

$\left(C_2{H}_{5}COOH\right)$ extrapolating $\wedge {{}^0}_m$ vs
$(Molarity{)}^{1/2}$ graph to

zero molarity.

C) IIonic conductance (R) Contribution by the

ion to $\wedge {{}^0}_m$

D) $\wedge {{}^0}_m$of $C{H}_{3}COOH$ (S) increases on dilution

• A. A-P,R: B-Q,S:C-S:D-S
• B. A-P,Q: B-P,S:C-S:D-P,S
• C. A-R: B-Q:C-R,S:D-P,Q
• D. A-S: B-Q,R:C-P:D-Q

Answer 1

Answer: (B)

A-P,Q: B-P,S:C-S:D-P,S

${NaNO}_3$ is a strong electrolyte. Its molar conductivity at zero concentration can be obtained by using kohlrausch law. It can also be obtained by extrapolating the graph of molar conductivty versus square root of concentration.
Propanoic acid is a weak electrolyte. Its molar conductivity at zero concentration can be obtained by using kohlrausch law. Its molar conductivity increases with dilution.
As the dilution increases, the value of ionic conductance increases.
Acetic acid is a weak electrolyte. Its molar conductivity at zero concentration can be obtained by using kohlrausch law. Its molar conductivity increases with dilution.