Question

Column 1: Molecular formula type

Column 2: Hybridisation of central atom

Column 3: Molecular shape

$\begin{array}{cccccc}& \text{Column 1}& & \text{Column 2}& & \text{Column 3}\\ \text{(I)}& A{B}_2& \text{(i)}& s{p}^2& \text{(P)}& \text{Linear}\\ \text{(II)}& A{B}_3& \text{(ii)}& s{p}^3& \text{(Q)}& \text{Planar}\\ \text{(III)}& A{B}_4& \text{(iii)}& s{p}^{3}d& \text{(R)}& \text{Pyramidal}\\ \text{(IV)}& A{B}_5& \text{(iv)}& s{p}^3{d}^2& \text{(S)}& \text{Tetrahedral}\end{array}$

The correct combination among the given options is:

• A. (I) (i) (P)
• B. (II) (ii) (Q)
• C. (III) (iv) (Q)
• D. (IV) (iii) (S)

Answer 1

The correct option is C (III) (iv) (Q)

(C) is possible in $Xe{F}_4$