2
Question
Column I
Column II
A
CH3−CHBr−CD3/on treatement with alc.KOH gives CH2=CH−CD3 as a major product
P
E1 reaction
B
Ph−CHBr−CH3 reacts faster than Ph−CHBr−CD3
Q
E2 reaction
C
Ph−CH2−CH2−F on treatement with C2H5OD/C2H5O−gives Ph−CD=CH2 as the major product
R
E1cB reaction
D
Ph−CH2−CH2−Br and Ph−CD2−CH2−Brreact with same rate
S
First order reaction
| Column I | Column II | ||
| A | CH3−CHBr−CD3/on treatement with alc.KOH gives CH2=CH−CD3 as a major product | P | E1 reaction |
| B | Ph−CHBr−CH3 reacts faster than Ph−CHBr−CD3 | Q | E2 reaction |
| C | Ph−CH2−CH2−F on treatement with C2H5OD/C2H5O−gives Ph−CD=CH2 as the major product | R | E1cB reaction |
| D | Ph−CH2−CH2−Br and Ph−CD2−CH2−Brreact with same rate | S | First order reaction |
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Solution
The correct option is A A−Q; B−Q; C−R, S; D−P ,S
A→Q
B→Q
C→R,S
D→P,S
In (A), the reactant, secondary alkyl halide reacts with alc. KOH. Alcoholic KOH is a strong base, it gives 1, 2 β− elimination product. Thus, it is a E2 elimination reaction.
In (B), the reactant is a benzyl halide derivative. Benyl halide undergoes both E1 and E2 elimination reaction. Here, Ph−CHBr−CH3 reacts faster than Ph−CHBr−CD3 which means the deuterium is involved in rate determining step. Hence, the given reaction is E2 elimination.
In (D), the reactant is a benzyl halide derivative. Benyl halide undergoes both E1 and E2 elimination reaction. Here, Ph−CH2−CH2Br and Ph−CD2−CH2Br reacts with same rate which means the deuterium is not involved in rate determining step. Hence, the given reaction is E1 elimination. 
A→Q
B→Q
C→R,S
D→P,S
In (A), the reactant, secondary alkyl halide reacts with alc. KOH. Alcoholic KOH is a strong base, it gives 1, 2 β− elimination product. Thus, it is a E2 elimination reaction.
In (B), the reactant is a benzyl halide derivative. Benyl halide undergoes both E1 and E2 elimination reaction. Here, Ph−CHBr−CH3 reacts faster than Ph−CHBr−CD3 which means the deuterium is involved in rate determining step. Hence, the given reaction is E2 elimination. In (D), the reactant is a benzyl halide derivative. Benyl halide undergoes both E1 and E2 elimination reaction. Here, Ph−CH2−CH2Br and Ph−CD2−CH2Br reacts with same rate which means the deuterium is not involved in rate determining step. Hence, the given reaction is E1 elimination.
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