wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Column I Column II
a. Joule- thomson coefficient p. (UV)T=0
b. Kirchhoff`s equation q. (2aRTb)
c. Ideal gas r. (ΔHT)P=ΔCP
d. Inversion temperature s. (TP)H=(H/P)TCP

A
(as)(br)(cp)(dq)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(ar)(bs)(cp)(dq)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(ap)(br)(cs)(dq)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(aq)(bp)(cr)(ds)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (as)(br)(cp)(dq)
(a) The rate of change of temperture T with respect to pressure P in a joule-Thompson process is the Joule Thompson (Kelvin) coefficient μjT
μjT=(TP)H=VCP(αT1)
(b) Kirchhoff's equation describes the enthalpy of a reaction's variation with temperature changes.
At constant pressure, the heat capacity is equal to change in enthalpy divided by the change in temperature.
(HT)P=CP
(c) For an ideal gas, (UV)T=0
(d) Inversion temperature is the critical temperature below which a non-ideal gas that is expanding at constant enthalpy will experience a temperature decrease and above which will experience a temperature increase.
Tinv=2abkB=2aRb

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Gibbs Free Energy
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon