Question

Column-I-Compound, Column-II-Oxidation state, Column-III-Type of linkage

$\begin{array}{cccccc}& Column1& & Column2& & Column3\\ \left(I\right)& N{a}_2{S}_2{O}_3& \left(i\right)& +5& \left(P\right)& S-O-S\\ \left(II\right)& N{a}_2{S}_4{O}_6& \left(ii\right)& -2& \left(Q\right)& S-S\\ \left(III\right)& H_2{S}_2{O}_7& \left(iii\right)& +6& \left(R\right)& -(O-O)-\\ \left(IV\right)& H_2{S}_2{O}_8& \left(iv\right)& +4& \left(S\right)& S=S\end{array}$

The only correct combination in which the hybridization of one of the S atom is $S{p}^2$.

• A. (I)(ii)(Q)
• B. (II)(i)(Q)
• C. (I)(ii)(S)
• D. (II)(i)(S)

Answer 1

The correct option is C

(I)(ii)(S)