Column-I-Compound- Column-II-Oxidation state- Column-III-Type of linkage beginarray - c-c-c-c-c-c-Whine- Column 1 - - Column 2 - - Column 3lllhlineI - Na - 2 S - 2 O - 3 - i -5 - P - S - O - Sll h hineII- Na2S4O6 - ii - -2 - Q - S-S llthlineIII - H2 S2 O7 - iii - -6 - R - -O-O-IllhlineIV - H2 S2 O8 - iv - -4 - S - S-SIWhline lendarray The only correct combination in which the oxidation state of one of the sulphur is zero-A- IiPB- IIiQC- IiQD- IIiP

The correct option is B (II)(i)(Q) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Preparation of Alkanes with Grignard Reagent

Column-I-Comp...

Question

Column-I-Compound, Column-II-Oxidation state, Column-III-Type of linkage

$\begin{matrix} C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (I) & N a_{2} S_{2} O_{3} & (i) & + 5 & (P) & S - O - S (I I) & N a_{2} S_{4} O_{6} & (i i) & - 2 & (Q) & S - S (I I I) & H_{2} S_{2} O_{7} & (i i i) & + 6 & (R) & - (O - O) - (I V) & H_{2} S_{2} O_{8} & (i v) & + 4 & (S) & S = S \end{matrix}$

The only correct combination in which the oxidation state of one of the sulphur is zero.

(II)(i)(P)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(I)(i)(P)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(II)(i)(Q)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(I)(i)(Q)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
(II)(i)(Q)

Suggest Corrections

Similar questions

Column-I-Compound, Column-II-Oxidation state, Column-III-Type of linkage

$\begin{matrix} C o l u m n 1 & C o l u m n 2 & C o l u m n 3 (I) & N a_{2} S_{2} O_{3} & (i) & + 5 & (P) & S - O - S (I I) & N a_{2} S_{4} O_{6} & (i i) & - 2 & (Q) & S - S (I I I) & H_{2} S_{2} O_{7} & (i i i) & + 6 & (R) & - (O - O) - (I V) & H_{2} S_{2} O_{8} & (i v) & + 4 & (S) & S = S \end{matrix}$

The only correct combination in which the hybridization of one of the S atom is $S p^{2}$ .

Column 1: Compound Column

Column 2: Oxidation state Column

Column 3: Type of linkage

$\begin{matrix} Column 1 & Column 2 & Column 3 (I) & N a_{2} S_{2} O_{3} & (i) & + 5 & (P) & S - O - S (I I) & N a_{2} S_{4} O_{6} & (i i) & - 2 & (Q) & - S - S - (I I I) & H_{2} S_{2} O_{7} & (i i i) & + 6 & (R) & - O - O - (I V) & H_{2} S_{2} O_{8} & (i v) & + 4 & (S) & S = S \end{matrix}$

The only correct combination in which the oxidation state of one of the S is zero:

Column 1: Compound

Column 2: Oxidation state

Column 3: Type of linkage

The only correct combination for Marshall’s Acid.

Column-I-Compound, Column-II-Oxidation state, Column-III-Type of linkage

The only correct combination for Marshall’s acid:

Column 1: Compound Column

Column 2: Oxidation state Column

Column 3: Type of linkage

The only correct combination for Oleum is:

Join BYJU'S Learning Program

Column-I-Compound, Column-II-Oxidation state, Column-III-Type of linkage Column 1Column 2Column 3(I)Na2S2O3(i)+5(P)S−O−S(II)Na2S4O6(ii)−2(Q)S−S(III)H2S2O7(iii)+6(R)−(O−O)−(IV)H2S2O8(iv)+4(S)S=S The only correct combination in which the oxidation state of one of the sulphur is zero.

The correct option is C (II)(i)(Q)

The correct option is C
(II)(i)(Q)