Question

Column-I lists type of decay and the Column-II lists reasons of decay (reason for unstability of nucleus)

$\begin{array}{cc}\text{Column - I}& \text{Column- II}\\ \text{(A)}\gamma -\text{decay}& \text{(P) Nucleus is too large}\\ \text{(B)}\alpha -\text{decay}& \text{(Q) Nucleus has too many neutrons}\\ & \text{relative to number of protons}\\ \text{(C)}{\beta }^{-}\text{decay}& \text{(R) Nucleus has excess energy}\\ \text{(D)}{\beta }^{+}\text{decay}& \text{(S) Nucleus has too many protons}\\ & \text{relative to number of neutrons}\\ & \text{(T) Takes place outside the nucleus}\end{array}$

• A. A-R; B-P;C-S;D-Q
• B. A-S;B-P;C-Q;D-R
• C. A-R;B-P;C-Q;D-S
• D. A-R;B-Q;C-P;D-S

Answer 1

The correct option is C A-R;B-P;C-Q;D-S

When the nucles is too heavy to bind itself, it sheds away mass by undergoing $\alpha$ decay.
If the neutrons are far too many, then to maintain a stable ratio of protons to neutrons, neutrons get converted to protons releasing electrons. This is nothing but ${\beta }^{-}$ decay.
If the protons are far too many, then to maintain a stable ratio of protons to neutrons, protons get converted to neutrons releasing positrons. This is nothing but ${\beta }^{+}$ decay.
And $\gamma$ decay is nothing but electromagnetic radiation which occurs when the nucles is at a higher state.