Question

	Column-I (Molecules)		Column-II (Property)
P	$I{F}_7$	1	Planar and polar
Q	$S{O}_2$	2	Non planar and polar
R	$S{F}_4$	3	Planar and non planar
S	$C{S}_2$	4	Non planar and non polar

• A. $P-4;Q-1;R-2;S-3$
• B. $P-4;Q-2;R-1;S-3$
• C. $P-3;Q-1;R-2;S-4$
• D. $P-3;Q-1;R-4;S-2$

Answer 1

The correct option is A $P-4;Q-1;R-2;S-3$

(P) $I{F}_7$
$\text{Hybridisation}:s{p}^3{d}^3$
Geometry: Pentagonal bipyramidal
Non-planar and non polar
(Q) $S{O}_2$
$\text{Hybridisation}:s{p}^2$
geometry: trigonal planar
Shape: V-shape or bent
Since, lone pair is present, it is a polar molecule.
(R) $S{F}_4$
$\text{Hybridisation}:s{p}^{3}d$
Geometry: trigonal bipyramidal
Shape: see saw
Since, $S{O}_2$ molecule is non-linear and lone pair is present, it is a polar molecule. Geometry is trigonal bipyramidal hence it is non-planar.
(S) $C{S}_2$
$\text{Hybridisation}:sp$
Geometry: Linear
Shape: linear
The molecular geometry of molecule is linear with symmetric electron region distribution around the central atom . Therefore this molecule is non-polar and planar.