Question

Column II gives $n^{th}$ term for AP given in column I. Match them correctly.
A. $119,136,153,\mathrm{170.....}$ 1. $13-3n$
B. $7,11,15,19,.....$ 2. $9-5n$
C. $4,-1,-6,-11,.....$ 3. $3+4n$
D. $10,7,4,\mathrm{3.....}$ 4. $17n+102$

• A. A $\to$ 3, B $\to$ 2, C $\to$ 1, D $\to$ 4
• B. A $\to$ 4, B $\to$ 3, C $\to$ 2, D $\to$ 1
• C. A $\to$ 3, B $\to$ 4, C $\to$ 2, D $\to$ 1
• D. A $\to$ 1, B $\to$ 3, C $\to$ 4, D $\to$ 2

Answer 1

The correct option is B A $\to$ 4, B $\to$ 3, C $\to$ 2, D $\to$ 1

By putting $n=1$ in general terms of all APs given, we get the first terms
$13-3n=13-3\left(1\right)=10$

So, D $\to$ 1
$9-5n=9-5\left(1\right)=4$

So, C $\to$ 2
$3+4n=3+4\left(1\right)=7$

So, B $\to$ 3
$17n+102=17\left(1\right)+102=119$

So, A $\to$ 1

Hence, the answer is A $\to$ 4, B $\to$ 3, C $\to$ 2, D $\to$ 1