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Question

Column- I
Physical quantity
Column-II
MKS system
Column-III
CGS system
Column- IV
FPS system
(A) length (a) newton (p) erg (1) poundal
(B) mass (b) m (q) dyne (2) ft-poundal
(C) force (c) kg (r) erg/s (3) ft
(D) power (d) joule (s) g (4) lb
(E) work (e) watt (t) cm (5) ft-poundal/s

A
(A)bt3
(B)cs4
(C)aq1
(D)er5
(E)dp2
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B
(A)cs3
(B)bs4
(C)at1
(D)er5
(E)dp2
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C
(A)dp3
(B)er4
(C)aq1
(D)cs5
(E)bt2
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D
None of these
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Solution

The correct option is A (A)bt3
(B)cs4
(C)aq1
(D)er5
(E)dp2

Length= meter , centimeter, feet
mass= kilogram, gram. pound(lb)
force= newton, dyne, poundal force
power= watt, work done per unit time (erg/sec) , ft-pundal/sec
work= joule, erg, ft- poundal
hence, the correct answer is A.

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