Question

Columns 1, 2 and 3 contain starting materials, reaction conditions, and type of reactions, respectively:
$\begin{array}{ccc}\text{Column 1}& \text{Column 2}& \text{Column 3}\\ \text{(I) Toluene}& \left(i\right)NaOH/B{r}_2& \text{(P) Condensation}\\ \text{(II) Acetophenone}& \left(ii\right)B{r}_2/hv& \text{(Q) Carboxylation}\\ \text{(III) Benzaldehyde}& \left(iii\right)(C{H}_{3}CO{)}_{2}O/C{H}_{3}COOK& \text{(R) Substitution}\\ \text{(IV) Phenol}& \left(iv\right)NaOH/C{O}_2& \text{(S) Haloform}\end{array}$The only CORRECT combination that gives two different carboxylic acids is:

• A. (IV) (iii) (Q)
• B. (III) (iii) (P)
• C. (II) (iv) (R)
• D. (I) (i) (S)

Answer 1

The correct option is B (III) (iii) (P)