Combustion of glucose is according to the following reaction C 6 H 12 O 6 s -6 O 2 g - 6 CO 2 g -6 H 2 O l - - H -2900 kJHow much heat energy if evolved in the combustion of 1-8 g of glucose-A- 15-2 kJB- 29 kJC- 8-47 kJD- None

The correct option is B 29 kJThe combustion equation for glucose is : C_6H_12O_6(s)+6O_2(g) → 6CO_2(g)+6H_2O(l); Δ H= 2900kJ Heat evolved in the combustion of ...

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Standard VIII

Chemistry

Calorific Value and Efficiency of a Fuel

Combustion of...

Question

Combustion of glucose is according to the following reaction
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J$
How much heat energy if evolved in the combustion of 1.8g of glucose?

15.2 kJ

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8.47 kJ

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29 kJ

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None

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Solution

The correct option is C 29 kJ
The combustion equation for glucose is :
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J Heat evolved in the combustion of 1 mole (or 180g) of glucose = 2900 k J ∴ \frac{2900}{180} \times 1.8 = 29 k J$

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Combustion of glucose is according to the following reaction C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l);ΔH=−2900kJ How much heat energy if evolved in the combustion of 1.8g of glucose?

The correct option is C 29 kJThe combustion equation for glucose is : C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l);ΔH=−2900kJHeat evolved in the combustion of 1 mole (or 180g) of glucose=2900kJ∴2900180×1.8=29kJ

Combustion of glucose is according to the following reaction
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J$
How much heat energy if evolved in the combustion of 1.8g of glucose?

The correct option is C 29 kJ
The combustion equation for glucose is :
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J Heat evolved in the combustion of 1 mole (or 180g) of glucose = 2900 k J ∴ \frac{2900}{180} \times 1.8 = 29 k J$