Combustion of glucose is according to the following reaction C6H12O6s-6O2g - 6CO2g-6H2Ol- - H-2900kJHow much heat energy if evolved in the combustion of 1-8g of glucose-

The combustion equation for glucose is : C_6H_12O_6(s)+6O_2(g) → 6CO_2(g)+6H_2O(l); Δ H= 2900kJ Heat evolved in the combustion of 1 mole (or 180g) of glucose=2 ...

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Standard XI

Chemistry

Enthalpy of Combustion

Combustion of...

Question

Combustion of glucose is according to the following reaction
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J$
How much heat energy if evolved in the combustion of 1.8g of glucose?

15.2 kJ

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8.47 kJ

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29 kJ

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Solution

The correct option is C 29 kJ
The combustion equation for glucose is :
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J Heat evolved in the combustion of 1 mole (or 180g) of glucose = 2900 k J ∴ \frac{2900}{180} \times 1.8 = 29 k J$

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Similar questions

Q. Combustion of glucose is according to the following reaction

C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J

How much heat energy if evolved in the combustion of 1.8g of glucose?

Q. Combustion of glucose takes place according to the equation.

C_{6} H_{12} O_{6} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O △ H = 0 = - 72 k - c a l

The energy required for combustion of

1.6 g

of glucose is:

Q. Combustion of glucose takes place according to the equation:

C_{6} H_{12} O_{6} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O, △ H = - 72 k c a l

The energy required for production of

1.6 g

of glucose is [molecular mass of glucose is

180 g m

]

Q. Calculate the standard free energy change for the combustion of glucose at

298 K

, using the given data.

C_{6} H_{12} O_{6} + 6 O_{2} (g) ⟶ 6 {C O}_{2} (g) + 6 H_{2} O

Δ H^{o} = - 2820 k J {m o l}^{- 1}; Δ S^{o} = 210 J K^{- 1} {m o l}^{- 1}

Q. Given a combustion reaction:

C_{6} H_{6 (l)} + \frac{15}{2} O_{2 (g)} \to 6 C O_{2 (g)} + 3 H_{2} O_{(l)}, Δ H = - 3264

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The energy (in kJ) evolved when

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Combustion of glucose is according to the following reaction C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l);ΔH=−2900kJ How much heat energy if evolved in the combustion of 1.8g of glucose?

The correct option is C 29 kJThe combustion equation for glucose is : C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(l);ΔH=−2900kJHeat evolved in the combustion of 1 mole (or 180g) of glucose=2900kJ∴2900180×1.8=29kJ

Combustion of glucose is according to the following reaction
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J$
How much heat energy if evolved in the combustion of 1.8g of glucose?

The correct option is C 29 kJ
The combustion equation for glucose is :
$C_{6} H_{12} O_{6} (s) + 6 O_{2} (g) \to 6 C O_{2} (g) + 6 H_{2} O (l); Δ H = - 2900 k J Heat evolved in the combustion of 1 mole (or 180g) of glucose = 2900 k J ∴ \frac{2900}{180} \times 1.8 = 29 k J$