Question

Combustion of glucose takes place according to the equation.
$C_6{H}_{12}{O}_6+6O_2\to 6C{O}_2+6H_{2}O△H=0=-72k-cal$
The energy required for combustion of $1.6g$ of glucose is:

• A. $0.064k-cal$
• B. $0.64k-cal$
• C. $6.4k-cal$
• D. $64k-cal$

Answer 1

The correct option is B $0.64k-cal$

Molar mass of $C_6{H}_{12}{O}_6=180gmo{l}^{-1}$
$\because 180g$ of glucose require energy $=72kcal$
$\therefore 1.6g$ of glucose required energy $=\frac{72\times 1.6}{180}$
$=0.64kcal$.