Question

Combustion of surose is used by aerobic organisms for providing energy for the life sustaining processes. If all the capturing of energy from the reaction is done through electrical process (non P-V work) then calculate maximum available energy which can be captured by combustion of $34.2gm$ of sucrose
Given : $\Delta H_{combustion}\left(sucrose\right)=-6000kJ.{mol}^{-1}$
$\Delta S_{combustion}=180J/K.mol$ and body temperature is $300K$

• A. $600kJ$
• B. $594.6kJ$
• C. $5.4kJ$
• D. $605.4kJ$

Answer 1

Answer: (D)

$605.4kJ$

As we know,

$\Delta G=\Delta H-T\delta S=-6000-300\times 0.18=-6054kJ/mol$

So, for 34.2gm (0.1 mol) of sucrose maximum available energy $\Delta G=605.4kJ$