Comment on the correctness of the following two statements.

Statement I – Net Electric field strength on a Gaussian surface may change if the charges inside or outside move.

Statement II – Electric flux through a Gaussian surface will not change if the charges contained inside do not cross the boundary of the assumed Gaussian surface.

True, True

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True, false

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False, True

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False, False

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Solution

The correct option is A
True, True

If the charges move, the field strength at the surface might change, as $| \to E | α \frac{1}{r^{2}}$

But flux is only due to charges inside the surface. So as long as no charge enters or leave, flux will remain unchanged. Hence both statements are correct.

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Similar questions

Comment on the correctness of the following two statements.

Statement I – Net Electric field strength on a Gaussian surface may change if the charges inside or outside move.

Statement II – Electric flux through a Gaussian surface will not change if the charges contained inside do not cross the boundary of the assumed Gaussian surface.

Comment on the correctness of the following two statements

Statement I => The electrical field calculated by Gauss’s law is the field only due to the charges inside the Gaussian surface.

Statement II => The flux of the electric field through a closed surface due to all the charges (inside and outside the surface), is equal to the flux only due to the charges enclosed by the surface.

Q. If net flux through a Gaussian surface is zero, then find whether the following statement is correct or not.
There are no charges inside the surface.

Q. If net flux through a Gaussian surface is zero, then find whether the following statement is correct or not.
The net charge inside the surface is zero.

Q. If net flux through a Gaussian surface is zero, then find whether the following statement is correct or not.
the electric field is zero everywhere on the surface.

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The correct option is A True, True If the charges move, the field strength at the surface might change, as |→E|α1r2 But flux is only due to charges inside the surface. So as long as no charge enters or leave, flux will remain unchanged. Hence both statements are correct.

The correct option is A
True, True

If the charges move, the field strength at the surface might change, as $| \to E | α \frac{1}{r^{2}}$

But flux is only due to charges inside the surface. So as long as no charge enters or leave, flux will remain unchanged. Hence both statements are correct.