Question

Comment on the E.N. of Sb in $Sb{F}_3$ and $Sb{F}_5$.

• A. E.N. of Sb $\left(Sb{F}_3\right)$ < E.N. of Sb $\left(Sb{F}_5\right)$
• B. E.N. of Sb $\left(Sb{F}_3\right)$ > E.N. of Sb $\left(Sb{F}_5\right)$
• C. E.N. of Sb is identical in both cases
• D. No comment can be predicated

Answer 1

The correct option is A E.N. of Sb $\left(Sb{F}_3\right)$ < E.N. of Sb $\left(Sb{F}_5\right)$

More is the positive charge more will be electronegativity.

Therefore, more electronegativity of Sb is in $Sb{F}_5$, as it has more $+$ve charge.