Comment on the existance of $B e_{2}$ .

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Solution

Be has electronic configuration $1 s^{2}, 2 s^{2}$ and s orbital is completely filled and doesn't require any electron to complete its orbital.
In $B e_{2}$ the total number of bonding electron is equal to total number of antibonding electron.
Hence, $B e_{2}$ doesn't exist at all.

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