Comment on the following statements A×(B∩C)=(A×B)∩(A×C)
Open in App
Solution
(x,y)∈A×(B∩C) ⇔(x∈A) and (y∈B∩C) (by def. of cross product) ⇔(x∈A) and (y∈Bandy∈C) ⇔(x∈Aandy∈B) and (x∈Aandy∈C) ⇔(x,y)∈(A×B) and (x,y)∈(A×C) ⇔(x,y)∈(A×B)∩(A×C) Hence A×(B∩C)=(A×B)∩(A×C)