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Stoichiometry

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Question

Comment on the peroxide and superoxide formed by Na and K.

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Solution

$N a$ (sodium) reacts with oxygen vigourously to form $N a_{2} O_{2}$ (peroxide)
$2 N a + O_{2} ⟶ N a_{2} O_{2}$
$K$ (potasium) reacts with oxygen to form superoxide.
$K + O_{2} \to K O_{2}$

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