Commercial available concentrate HCl contain 38percent HCl by mass. What is the molarity of this solution. Density is 1.19g per cm3

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Concentrated HCl 38% by mass i.e 100gm of HCL soclution contains 38gm of HCl moles of HCl = given mass/molar mass = 38/36.5 Now density of solution = 1.19 g mL-1Since solution is 100gm. Density = Mass/volume = Volume= mass/density = 100/1.19 ml Molarity = Moles of Solute/volume of Solution in L M = (38/36.5)(10001.19/100) = 12.38 M

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38

H C l

(i)

1.19 g m L^{- 1}

(i i)

H C l

1.0 L

0.10 M H C l ?

Commercialy available concentrated HCl contains 38% HCl by mass ?

1) What is the molarity of the solution ? ( d = 1.19 g/mL)

2) What volume of concentrated HCl is required to make 1 L of 0.1 M of HCL ?

H C l

38 %

H C l

Comercially available concentrated HCL contains 38% HCL by mass.

i . What is molarity of the solution.(d=1.19ml).

ii . What volume of conc. HCL is required to make 1L of 0.1 M HCL.

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