Question

Commercially available conc. HCl contains 38% HCl by mass, what is the molarity of the solution, density of solution = 1.19 g/ml. What volume of conc. HCl is required to make 10. L of an 0.10 M HCl

Answer 1

density of solution = $1.19$ glml

Molarity = $\frac{1.19}{MolarmassofHCl}\times 1000\times 38\%$

$=\frac{1.19}{36.5}\times 1000\times \frac{38}{100}$

$12.389m$

mole of HCl required to make 10 L of all $0.1MHCl=10\times 0.1=1mole$

$12.389\times v=1$

$v=\frac{1}{12.389}=80.7ml$