Question

The common factors of $17abc,34a{b}^2$ and $51a^{2}b$ is

• A. $17abc$
• B. $17ab$
• C. $17ac$
• D. $17a^2{b}^{2}c$

Answer 1

The correct option is B

$17ab$

Explanation for the correct option:

A whole number is said to be a common factor of two or more numbers if it completely divides them.

The factors of $17abc$ :

$17abc=1\times 17\times a\times b\times c$

Similarly, the factors of $34a^{2}b$ :

$34a^{2}b=1\times 2\times 17\times a\times a\times b$

And, the factors of $51a^{2}b$ :

$51a^{2}b=1\times 3\times 17\times a\times a\times b$

Therefore, the common factors of $17abc,34a^{2}b$ and $51a^{2}b$:

$$\begin{gathered} 1\times 17\times a\times b \\ =17ab \end{gathered}$$

Hence, the correct option is (b) i.e. $17ab$.