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Question

Common roots of the equation z3+2z2+2z+1=0 and z1985+z100+1=0 are

A
ω,ω2
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B
1,ω,ω2
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C
1,ω,ω2
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D
ω,ω2
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Solution

The correct option is A ω,ω2
z3+2z2+2z+1=0 ___ (1)

z1985+z100+1=0 ___ (2)

We know that 1+ω+ω2=0,ω3=1
check ω to be root,
(1) ω3+2ω2+2ω+1
=1+ω+ω2+1+ω+ω2=0+0=0
(2) ω1985+ω100+1ω2+ω+1=0
ω is a common root

check ω2 to be a root
(1) ω6+2ω4+2ω2+1

= (ω3)2+2ω(ω3)+2ω2+1

= 1+ω+ω2+1+ω+ω2=0

(2)= ω3970+ω200+1

= ω+ω2+1=0
ω2 is a common root
A is correct

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