common salt obtained from sea water contains 8.775 % NaCl by mass. what is the number of formula units of NaCl present in 25 gram of this salt

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Solution

$8.775 % b y m a s s m e a n s 8.775 g o f N a C l i s p r e s e n t i n 100 g s a m p l e S o 25 g o f t h e s a m p l e c o n t a i n s = \frac{8.775}{100} \times 25 = 2.193 g o f N a C l 58.5 g o f N a C l = M o l e c u l a r m a s s = A v o g a d r o n o o f p a r t i c l e s = 6.022 \times 10^{23} o f N a C l u n i t c e l l 2.193 g o f N a C l c o n t a i n s = \frac{2.193}{58.5} \times 6.023 \times 10^{23} = 2.258 \times 10^{22} N a C l u n i t s$

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